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I have an extra credit problem for my algebra 2 class that I've been working on with a friend for over an hour and we cannot find the answer. I'll give a 135 influence turf to whoever can give me the answer and another 135 for telling me how they got it.
One mile upstream from her starting point, a rower passed a stick floating with the current. After rowing upstream for one more hour, she rowed back and reached her starting point just as the stick arrived. How fast was the current flowing?
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Need more numbers.
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ThatTallKid_ wrote:
That's the whole question lolNeed more numbers.
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U got 3 variables
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Half as fast as the rower?
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Funky Buffalo wrote:
I don't really think that's a possible answer lol. Gotta be a numberHalf as fast as the rower?
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.333?
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Funky Buffalo wrote:
Would be 1/3 cuz the rower covers 3 miles, and the stick covers only 1Half as fast as the rower?
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YOU wrote:
Nvr mind give me a sec that's not right..333?
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♛Çąŋժूƴɱąŋ♛ wrote:
The rower covers 2 miles, 1 hour, and another undisclosed amount of time and distanceFunky Buffalo wrote:
Would be 1/3 cuz the rower covers 3 miles, and the stick covers only 1Half as fast as the rower?
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Assuming the rower travels at a constant rate of speed (both upstream and downstream, which is bogus), then the stick is traveling at 1/3 the speed of the rower (moves one "segment" while the rower moves 3 segments). We're told that the rower is traveling at 1 mile per hour, thus the current (stick) is moving at 1/3 mph. Reality would require the rower to travel downstream faster than upstream. If you assume constant effort by the rower (without tiring), and also assume the rower moves twice as fast downstream as upstream, then the stick moves one segment in the same amount of time as the rower moving two segments (1 at speed x, and 2 at speed 2x). Therefore, the current is moving at 0.5 mph. Too many assumptions to resolve exactly!
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1/4. Because she went 2 miles up while the log started at 1 mile and then went back to the starting point as the rower arrived so for the stick to get there it would take 15 min and rower had to row back down stream.
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Doc Xray wrote:
The current affects the speed directly, so if the rower is going 5mph and the current is going 3mph, the rower will go 2mph upstream and 8mph downstream. We also don't know that the rower traveled 1mph. We just know that the rower traveled for 1 mile and then continued at the same pace for another hour before going downstream✂
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This is actually a bogus question. They started 1 mile upstream (who knows how long it took) then traveled an unknown distance for another hour. You need to know the distance and time it took for them to get there to figure out how fast the stick is going.
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Doc Xray wrote:
Actually the rower covers four segments as she rows up for an hour and a mile and then back for an hour and a mileAssuming the rower travels at a constant rate of speed (both upstream and downstream, which is bogus), then the stick is traveling at 1/3 the speed of the rower (moves one "segment" while the rower moves 3 segments). We're told that the rower is traveling at 1 mile per hour, thus the current (stick) is moving at 1/3 mph. Reality would require the rower to travel downstream faster than upstream. If you assume constant effort by the rower (without tiring), and also assume the rower moves twice as fast downstream as upstream, then the stick moves one segment in the same amount of time as the rower moving two segments (1 at speed x, and 2 at speed 2x). Therefore, the current is moving at 0.5 mph. Too many assumptions to resolve exactly!
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ṩøʊ₮ℌㄕ∆ω wrote:
We can't conclude that the rower travels 1mph. We're only told that she travels 1 mile and then another hour1/4. Because she went 2 miles up while the log started at 1 mile and then went back to the starting point as the rower arrived so for the stick to get there it would take 15 min and rower had to row back down stream.
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As it says another hour. It would seem that the rower is traveling at the very most one mile per hour
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.3mph
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I think a system of equations is the best approach for this problem as that's the only way I know to solve a problem with two variables(the sticks speed and the rowers speed)
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Just tell your teacher if she gives it to you you'll give her 4 135 influence turfs.
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YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer. -
It never says that he travels 1mph, the first mile could have taken him three hours then he told himself ok one more hour and I'm turning around
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YOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁 -
ThatTallKid_ wrote:
That's why it's EC😝YOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁 -
Joyride 🚗💨 wrote:
He has to be going at a constant rate if no other numbers are given. I'm assuming. It's algebra so might have to make some sort of system of equation like a substition formula or whatever they're teaching you.It never says that he travels 1mph, the first mile could have taken him three hours then he told himself ok one more hour and I'm turning around
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ThatTallKid_ wrote:
Except that even if the rower was going 1mph she covered 4 milesYOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁 -
ThatTallKid_ wrote:
.83 is too fast but .33 may be correct. I'll check itYOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁 -
Doc Xray wrote:
👆👆👆👆thisAssuming the rower travels at a constant rate of speed (both upstream and downstream, which is bogus), then the stick is traveling at 1/3 the speed of the rower (moves one "segment" while the rower moves 3 segments). We're told that the rower is traveling at 1 mile per hour, thus the current (stick) is moving at 1/3 mph. Reality would require the rower to travel downstream faster than upstream. If you assume constant effort by the rower (without tiring), and also assume the rower moves twice as fast downstream as upstream, then the stick moves one segment in the same amount of time as the rower moving two segments (1 at speed x, and 2 at speed 2x). Therefore, the current is moving at 0.5 mph. Too many assumptions to resolve exactly!
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Lady Katsa wrote:
He was already 1 mile from starting point so he covered 3 units. I'm assuming again.ThatTallKid_ wrote:
Except that even if the rower was going 1mph she covered 4 milesYOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁 -
ωⅇɢṡɪⅇṣ wrote:
If its .333 then I win 😄ThatTallKid_ wrote:
.83 is too fast but .33 may be correct. I'll check itYOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁 -
☪Λaгѳԓ☪ wrote:
Not so fast Aaron had to show math😄ωⅇɢṡɪⅇṣ wrote:
If its .333 then I win 😄ThatTallKid_ wrote:
.83 is too fast but .33 may be correct. I'll check itYOU wrote:
2.5/3= .83mph. I dunno that's what I got.YOU wrote:
The guy is going 1mph. He goes 3 miles back to his starting point. The stick covers 1 mile in 3 hrs so .3mph..3mph
That might be wrong so 2.5m/3hrs➡ Is your answer.
Either .3mph or .83mph is your answer. I don't remember Algebra 2 freshman year with those kind of problems😁
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